MI Won By 7 Wickets: Rohit’s 70, Boult 4 Wickets, MI Claim 3 Spot

In the 41st IPL 2025 match, which took place on April 23 at Hyderabad's Rajiv Gandhi International Stadium, the Mumbai Indians (MI) defeated the Sunrisers Hyderabad (SRH) by a dominant seven wickets. This victory was their fourth straight and moved them up to third position in the standings.

Match Summary

H Klaasin’s 71 massive inning, but Boult’s 4 wickets performance, SRH only score 143

SRH faced early difficulties after losing the toss and being put in to bat, falling to 35/5 in the first nine overs.Together with Abhinav Manohar's 43, Heinrich Klaasen's 71 runs throughout a strong innings let SRH rally to 143/8 in their 20 overs. With four wickets for 26 runs, Trent Boult was MI's most impressive bowler. Deepak Chahar also made a contribution with two wickets for 12 runs.

Rohit Sharma’s explosive inning of 70 runs, cameo of SKY’s 40 runs, MI achieve target in 15.4 overs

MI's innings was guided by Rohit Sharma, who produced a fluid 70 runs off 46 balls as they chased a goal of 144.With seven wickets remaining and an undefeated 40, Suryakumar Yadav gave MI strong assistance as they won in just 15.4 overs. 

MI Claim The 3 Spot, SRH Need To Win Upcoming Matches

MI's dominating performance demonstrates their excellent tournament form, while SRH will need to regroup to raise their rankings.

 

IPL 2025 POINTS TABLE